11498: Division of Nlogonia

解題心得

沒有心得。

程式碼

#include <iostream>
using namespace std;

int main()
{
	int t, n, m, x, y;
	while (cin >> t && t)
	{
		cin >> n >> m;
		while (t--)
		{
			cin >> x >> y;
			if (x > n && y > m)
				cout << "NE" << endl;
			else if (x < n && y > m)
				cout << "NO" << endl;
			else if (x > n && y < m)
				cout << "SE" << endl;
			else if (x < n && y < m)
				cout << "SO" << endl;
			else
				cout << "divisa" << endl;
		}
	}
	return 0;
}