解題思路
中規中矩的 binary search tree。
程式碼
class Solution {
public:
int search(vector<int>& nums, int target) {
int left = 0, right = nums.size() - 1;
while(left <= right)
{
int mid = (left + right) / 2;
if(nums[mid] == target)
return mid;
else if(nums[mid] < target)
{
left = mid + 1;
}
else
{
right = mid - 1;
}
}
return -1;
}
};
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